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➜ ROM
➜ Compiling the server
➜ Changing #define A 1 to .... (this might belong somewhere else)
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Changing #define A 1 to .... (this might belong somewhere else)
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It is now over 60 days since the last post. This thread is closed.
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| Posted by
| Greystar
USA (2 posts) Bio
|
| Date
| Fri 09 Aug 2002 09:52 PM (UTC) |
| Message
| What I want to do is change the #define structure for Letters.
from
/* RT ASCII conversions -- used so we can have letters in this file */
#define A 1
#define B 2
#define C 4
#define D 8
#define E 16
#define F 32
#define G 64
#define H 128
#define I 256
#define J 512
#define K 1024
#define L 2048
#define M 4096
#define N 8192
#define O 16384
#define P 32768
#define Q 65536
#define R 131072
#define S 262144
#define T 524288
#define U 1048576
#define V 2097152
#define W 4194304
#define X 8388608
#define Y 16777216
#define Z 33554432
#define aa 67108864
#define bb 134217728
#define cc 268435456
#define dd 536870912
#define ee 1073741824
to something like
#define A 01
#define B 02
#define C 03
#define D 04
#define E 05
#define F 06
#define G 07
#define H 08
#define I 09
#define J 0A
#define K 0B
#define L 0C
#define M 0D
#define N 0E
#define O 0F
#define P 10
#define Q 11
#define R 12
#define S 13
#define T 14
#define U 15
#define V 16
#define W 17
#define X 18
#define Y 19
#define Z 1A
#define aa 1B
#define bb 1C
#define cc 1D
#define dd 1E
#define ee 1F
I want to do this to see if I can increase my allowable flags to include
#define ff 20
...
#define zz 34
Obviously I want to change them to hex code.
What I want to know is:
Has anyone done this?
Is it effective to extend the allowable flags though zz?
Does it require a lot of changes to a stock rom code?
Any suggestions are appreciated, flames to a minimum please.
Thanks | | Top |
|
| Posted by
| Nick Gammon
Australia (23,173 posts) Bio
Forum Administrator |
| Date
| Reply #1 on Sat 10 Aug 2002 12:55 AM (UTC) |
| Message
| Your idea won't work as presented, sorry.
The problem is that each flag must be a unique 'bit' in the resulting word in memory.
For example, your idea of defining C as 3, means if you used C it would also match A and B.
Look at it from the bit pattern point of view and you'll see what I mean:
A 0001
B 0010
C 0011
In the original system each new flag is a power of 2, (2, 4, 8, 16 and so on). So the original system looks like this:
A 0001
B 0010
C 0100
D 1000
So you see that the bits don't overlap. Thus, you can have flags A and B set (which will be 0011). In your system you would have no way of distinguishing between A and B set (0011) and C being set (0011).
The original system squeezes as many flags as it can into a 32-bit word (actually there seem to be 31 of them, A-Z plus aa-ee, which probably is because they didn't want to use the 'sign' bit which is the 32nd. bit).
Your only option is to use another field (ie. another 32 bits). |
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
| Posted by
| Nick Gammon
Australia (23,173 posts) Bio
Forum Administrator |
| Date
| Reply #2 on Sat 10 Aug 2002 12:59 AM (UTC) |
| Message
| Writing them in hex does't change the underlying problem, and in any case my example shows that the system falls down even in the case of 1 to 3, which is the same in hex and decimal.
BTW - if you wanted to write in hex the syntax is:
#define M 0x0D
(Your system would compile OK, it would just behave *very* strangely when you tried to use the flags). |
- Nick Gammon
www.gammon.com.au, www.mushclient.com | | Top |
|
| Posted by
| Greystar
USA (2 posts) Bio
|
| Date
| Reply #3 on Sun 11 Aug 2002 02:48 AM (UTC) |
| Message
| | Thanks! I think I got what I want now though. I got it so it works with 64 bits... still testing though. | | Top |
|
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