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Need help with regexp
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Posted by
| Gunner
Argentina (30 posts) bio
|
Date
| Tue 30 Mar 2021 03:51 AM (UTC) Amended on Tue 30 Mar 2021 04:48 AM (UTC) by Nick Gammon
|
Message
| Hello.
I am trying to validate text input from an input box.
What I need is for the character string to match a word (not numbers) or two words separated by a space
the function is:
function comprobar_hechizo (dhech)
local match = string.match (dhech, "^%%a+%%s%%a+$")
if not n then
utils.msgbox ("the spell name can only contain letters and spaces", "Error")
return false
end
return true
end
This only works if the string contains two words and a space, but I also want it to work if the string contains only one word.
I have tried this:
local match = string.match (dhech, "^%%a+|%%a+%%s%%a+$")
But don't work. | top |
|
Posted by
| Nick Gammon
Australia (22,928 posts) bio
Forum Administrator |
Date
| Reply #1 on Tue 30 Mar 2021 04:35 AM (UTC) |
Message
| What's with the two % symbols?
Anyway, Lua patterns don't have optional things (however the PCRE regexps, used in triggers, do).
You could do this:
test = "foo bar"
if string.match (test, "^[%a%s]+$") then
print "ok"
else
print "fail"
end
That will test for letters and spaces, so it would match one word, two words, three or more words, or even a single space.
A better thing would be to have two tests (one word, or two words) like this:
test = "foo bar"
if string.match (test, "^%a+$") or string.match (test, "^%a+%s+%a+$") then
print "ok"
else
print "fail"
end
|
- Nick Gammon
www.gammon.com.au, www.mushclient.com | top |
|
Posted by
| Nick Gammon
Australia (22,928 posts) bio
Forum Administrator |
Date
| Reply #2 on Tue 30 Mar 2021 04:40 AM (UTC) Amended on Tue 30 Mar 2021 04:41 AM (UTC) by Nick Gammon
|
Message
| Although this might work:
test = "foo bar"
if string.match (test, "^%a+%s*%a*$") then
print "ok"
else
print "fail"
end
That is testing for:
- One or more letters (so you get at least one word)
- Zero or more spaces (so the space is optional)
- Zero or more extra letters (to allow for the second word)
See: http://www.gammon.com.au/scripts/doc.php?lua=string.find |
- Nick Gammon
www.gammon.com.au, www.mushclient.com | top |
|
Posted by
| Gunner
Argentina (30 posts) bio
|
Date
| Reply #3 on Tue 30 Mar 2021 04:52 AM (UTC) |
Message
|
Nick Gammon said:
A better thing would be to have two tests (one word, or two words) like this:
test = "foo bar"
if string.match (test, "^%a+$") or string.match (test, "^%a+%s+%a+$") then
print "ok"
else
print "fail"
end
Perfect, that has worked for me.
As for the double%, that function is inside a send in an alias | top |
|
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